Could any one please explain to me how to solve them thanks =)

http://i307.photobucket.com/albums/n...n/homework.jpg

Printable View

- Jan 4th 2009, 05:27 PMSteven2algebra 2 help
Could any one please explain to me how to solve them thanks =)

http://i307.photobucket.com/albums/n...n/homework.jpg - Jan 4th 2009, 05:50 PMmr fantastic
I'll help with Q2: $\displaystyle y = \frac{x^2 - 4}{2x^2 + 5x - 12}$.

**x -int:**Apply the definition: Solve $\displaystyle x^2 - 4 = 0$.

**Vertical asymptote:**Apply the definition: Solve $\displaystyle 2x^2 + 5x - 12 = 0$.

**Horizontal asymptote:**Apply the definition and consider the limit as $\displaystyle x \rightarrow \pm \infty$.

Two options:

1. From polynomial long division $\displaystyle y = \frac{x^2 - 4}{2x^2 + 5x - 12} = \frac{1}{2} - \frac{5x-4}{2(2x^2 + 5x - 12)}$.

2. $\displaystyle y = \frac{x^2 - 4}{2x^2 + 5x - 12} = \frac{1 - \frac{4}{x^2}}{2 + \frac{5}{x} - \frac{12}{x^2}}$.

Either way, $\displaystyle y \rightarrow 2$ .... - Jan 4th 2009, 06:13 PMSteven2
Thanks for the response but could you help me factor the denominator.

Example X^2-9x+18 factors out to (x-3)(X-6)

Just cant seem to factor this problem.(Crying) - Jan 4th 2009, 06:24 PMmr fantastic