Binomial Theorem

**jenny woodland** · January 4th 2009, 04:23 PM

Is it possible to solve this problem? If so , how do I go about it?

Expand the following equation (1 +1/x) ^ -1 in ascending powers of x up to and including the term in X^3.

**Mush** · January 4th 2009, 04:37 PM

Blah...

**Danny** · January 4th 2009, 04:41 PM

Originally Posted by jenny woodland

Is it possible to solve this problem? If so , how do I go about it?

Expand the following equation (1 +1/x) ^ -1 in ascending powers of x up to and including the term in X^3.

Try

$\left( 1 + \frac{1}{x} \right)^{-1} = \left( \frac{1+x}{x} \right) ^{-1} = \frac{x}{1+x} = x \left( 1 + x\right)^{-1}$

and look for an expansion for $\left( 1 + x\right)^{-1}$ (once again, too slow. Mush - I don't understand?)

**jenny woodland** · January 5th 2009, 02:31 AM

Thanks for that answer, Danny.

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