Complete the square for 3x^2 - 7x+ 12 = 0

MY WORK:

I know that the coefficient of the x^2 term must be 1 in order to complete the square.

I divided everything by 3 and came up with this:

x^2 -(7x/3) + 4 = 0

I then subtracted 4 from both sides and got this:

x^2 - (7x/3) = -4

I then took 1/2 of -7/3, which is 14/9, and squared that to add to both sides and got this:

x^2 - (7x/3) + (196/81) = -4 + (196/81)

Where do I go from there?