The Cube of a number divided by nine equals three. Is this right x^2/9=3 Please explain well
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Originally Posted by frankpham12 The Cube of a number divided by nine equals three. Is this right x^2/9=3 Please explain well Cube (=3) so $\displaystyle \frac{x^3}{9} = 3$
well fist off if its a cube, it would be $\displaystyle x^3/9 = 3$ $\displaystyle x^3 = 9*3$ $\displaystyle x^3 = 9*3$ $\displaystyle x^3 =27$ $\displaystyle x = 3$
ha i messed up the cube with the squared
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