1. this is another question.

what i tried to do is :

x=b,

(b^2) + pb +q = 3(b^2) +q
-2(b^2) + pb = 0

and then.....i'm stuck. ="=
i think my beginning is already incorrect. =_=

2. A tip: Always use new threads for new questions. Your problem will get attention faster. People always tend to answer new posts than old ones.

Originally Posted by wintersoltice

(b^2) + pb +q = 3(b^2) +q
-2(b^2) + pb = 0
Instead of the above equation, write it as:

(b^2) + pb +q = 0; --------------------------(1)
3(b^2) +q = 0;--------------------------(2)

Multiply the first equation by 3 and subtract the second from it.

$(3b^2 + 3pb + 3q) - (3b^2 +q ) = 0$ $\Rightarrow 3pb + 2q = 0 \Rightarrow 9p^2b^2 = 4q^2$

Now eliminate $b^2$ from the above equation and equation (2).