Originally Posted by
HallsofIvy You can solve polynomial equations by factoring right? If p(x)= (x-a)(x-b)(x-c) then x= a, x= b, and x= c are the zeros. And the fact that the coefficient of each x is 1 means that the leading coefficient after you have multiplied it out will be 1. The answer to the problem as you have stated it is (x- 4)(x+ 4)(x+ 3i).
WARNING! You did NOT say that the polynomial must have real coefficients! For example, the constant term of that would be -48i. If you are also required to have real coefficients you will need the "complex conjugate" also as a zero: (x-4)(x+4)(x+ 3i)(x-3i).