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**HallsofIvy** You can solve polynomial equations by factoring right? If p(x)= (x-a)(x-b)(x-c) then x= a, x= b, and x= c are the zeros. And the fact that the coefficient of each x is 1 means that the leading coefficient after you have multiplied it out will be 1. The answer to the problem **as you have stated it** is (x- 4)(x+ 4)(x+ 3i).

WARNING! You did NOT say that the polynomial must have **real** coefficients! For example, the constant term of that would be -48i. If you are also required to have real coefficients you will need the "complex conjugate" also as a zero: (x-4)(x+4)(x+ 3i)(x-3i).