Thread: Trouble with a number prob.

Two numbers add up to 43. Four times the first is four more than twice the second. What are the numbers? Im stuck on this one, lol. Any help would be awesome, thanks.

Originally Posted by Nate

Two numbers add up to 43. Four times the first is four more than twice the second. What are the numbers? Im stuck on this one, lol. Any help would be awesome, thanks.

Call one number x
Then the other is 43 - x as they add up to 43

Four times the first is 4x

Twice the second is 2(43 - x) = 86 - 2x
Then 4 more is 86 - 2x + 4 = 90 - 2x

So 4x = 90 - 2x

6x = 90

x = 15
43 - x = 28

Thats so easy now. Thanks so much for the help; grately appreciated.

Originally Posted by Nate

Two numbers add up to 43. Four times the first is four more than twice the second. What are the numbers? Im stuck on this one, lol. Any help would be awesome, thanks.

x+y=43
4x=2y+4

In first equation subtract 'y' from both sides:
x=43-y

In second equation substitute 'x' from first equation:
4(43-y)=2y+4

Simplify by dividing by 2,
2(43-y)=y+2

Open parantheses,
86-2y=y+2

Add '2y' to both sides,
86=3y+2

Subtract 2 from both sides,
84=3y

Divide by 3,
y=28

Then,
x=43-y=43-28=15