Suppose f(x)= 10^-x, find f[log[1/10]]. How do you solve this? Are they looking for Inverse?? Thanks, Joe.
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Originally Posted by usrnme14 Suppose f(x)= 10^-x, find f[log[1/10]]. How do you solve this? Are they looking for Inverse?? Thanks, Joe. Note that $\displaystyle \log\left(\tfrac{1}{10}\right)=\log\left(10^{-1}\right)=-\log\left(10\right)=-1$ So what do think that $\displaystyle f\left(-1\right)$ equals?
10?
Originally Posted by usrnme14 10?
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