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Math Help - This may be a stupid question, but...

  1. #1
    Junior Member
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    This may be a stupid question, but...

    How does (cosh squared x - sinh squared x) / (cosh squared x) equal

    1 - ((sinh x / cosh x)^2)

    Help appreciated!
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  2. #2
    Super Member flyingsquirrel's Avatar
    Joined
    Apr 2008
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    802
    Hi,

    \frac{\cosh^2x-\sinh^2x}{\cosh^2x}=\frac{\cosh^2x}{\cosh^2x}-\frac{\sinh^2x}{\cosh^2x}=1-\frac{\sinh^2x}{\cosh^2x}=1-\left(\frac{\sinh x}{\cosh x}\right)^2
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  3. #3
    Junior Member
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    Thank you SO much. You're a star!
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