How does (cosh squared x - sinh squared x) / (cosh squared x) equal 1 - ((sinh x / cosh x)^2) Help appreciated!
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Hi, $\displaystyle \frac{\cosh^2x-\sinh^2x}{\cosh^2x}=\frac{\cosh^2x}{\cosh^2x}-\frac{\sinh^2x}{\cosh^2x}=1-\frac{\sinh^2x}{\cosh^2x}=1-\left(\frac{\sinh x}{\cosh x}\right)^2$
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