Solve for x. My solution is attached but I don't know the next step.
You got a little misconstrued.
$\displaystyle \frac{log(x+2)}{log(2)}=\frac{log(8)}{log(2)}-\frac{log(x)}{log(2)}$
$\displaystyle log(x+2)+log(x)=log(8)$
$\displaystyle log(x(x+2))=log(8)$
$\displaystyle x^{2}+2x-8=0$
There will be two solutions, only one is valid.