I don't know how to solve this.
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Originally Posted by mwok I don't know how to solve this. Take natural logarithms of both sides, noting that: $\displaystyle ln(e^{f(x)}) = f(x) $
Take not lne = 1 e^1-2x = 5 lne^1-2x = ln 5 ( ln both sides ) 1-2x(lne) = ln5 1-2x = ln5 2x = 1-ln5 x = 1-ln5/2
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