The variables x, y, z satisfy the equations

x + 2y + 3y = 2

x + 3y + 2z = 1

2x + 2y + 𝛌z = 𝛍

where, 𝛌, 𝛍 are constants

a) using reduction to echelon form, or otherwise,

i) Find the value of 𝛌 for which these equations do not have a unique solution

ii) for this value of 𝛌, find the value of 𝛍 for which the equations are consistent.

b) for your values of 𝛌,𝛍, find the general solution of these equations.

I have managed to reduce the equations to

x + 2y + 3z = 2

0 - y + z = 1

0 + 0 + 8-𝛌 = 6-𝛍

I'm not sure what to do next as i'm not sure what it means'or which these equations do not have a unique solution'

Has anybody got any ideas?

thanks