solve for x

8(5^2x) + 8(5^x) = 6

ALSO!

(3^5x)(9^x^2)= 27 solve for x

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- Dec 17th 2008, 10:02 PMcapitalhNeed help!! test in 7 hours!!!
solve for x

8(5^2x) + 8(5^x) = 6

ALSO!

(3^5x)(9^x^2)= 27 solve for x - Dec 17th 2008, 10:25 PMo_O
#1:

This is basically a quadratic. To see it more easily, let .

Then our quadratic becomes:

Factor to solve for .

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#2: Is this your question:

If so, try to get everything under the same base using your exponent laws:

Since the bases are equal, then the exponents should be equal, i.e. - Dec 17th 2008, 10:28 PMGrandadIndices and logs
Hi -

So the equation can be re-writtenL

Substitute to get a quadratic in . Solve and then use to find .

Quote:

(3^5x)(9^x^2)= 27 solve for x

... can you do the next step? [Hint: ]

You then get a quadratic in which you can solve.

Grandad - Dec 17th 2008, 11:03 PMcapitalh
thanks guys!