Hi im wondering if you can help. f(x)= ax^2 +bx+c If f(1)=6, f(-1)=8 and f(-2)= 18. Find f(2) Note ^ means power of.
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The answer is f(2)=14. I dont know were the answer comes from, i was thinking simultaneous equations
Originally Posted by leavingcertmaths Hi im wondering if you can help. f(x)= ax^2 +bx+c If f(1)=6, f(-1)=8 and f(-2)= 18. Find f(2) Note ^ means power of. Observe that: f(2) = f(-2) + 2(f(1) - f(-1))
Originally Posted by Isomorphism Observe that: f(2) = f(-2) + 2(f(1) - f(-1)) I understand that when you sub in the values for the equation above that you get that f(2)=14 but were did you get this equation?
The identity comes from substitution: f(2) = 4a+2b+c f(-2) = 4a -2b+c f(-1) = a - b+c f(1) = a+b+c
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