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Math Help - Solve for x logarithm

  1. #1
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    Solve for x logarithm

    Attached is the question and possible solution. Is it correct?
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  2. #2
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    log(x+99)-log(3x-2)=2

    Rewrite:

    log\left(\frac{x+99}{3x-2}\right)=2

    \frac{x+99}{3x-2}=100

    x+99=300x-200

    -299x=-299

    x=1
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  3. #3
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    It is not correct. Should be :

    log(x+99) - log(3x-2) = 2
    log( x+99 / 3x-2 ) = 2
    x+99 / 3x-2 = 10^2
    x+99 = 100(3x-2)
    x+99 = 300x - 200
    299x = 299
    x = 1
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