Attached is the question and possible solution. Is it correct?

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- Dec 17th 2008, 08:00 AMmwokSolve for x logarithm
Attached is the question and possible solution. Is it correct?

- Dec 17th 2008, 08:10 AMgalactus

Rewrite:

- Dec 17th 2008, 08:10 AMtester85
It is not correct. Should be :

log(x+99) - log(3x-2) = 2

log( x+99 / 3x-2 ) = 2

x+99 / 3x-2 = 10^2

x+99 = 100(3x-2)

x+99 = 300x - 200

299x = 299

x = 1