# Solve for x logarithm

• December 17th 2008, 07:00 AM
mwok
Solve for x logarithm
Attached is the question and possible solution. Is it correct?
• December 17th 2008, 07:10 AM
galactus
$log(x+99)-log(3x-2)=2$

Rewrite:

$log\left(\frac{x+99}{3x-2}\right)=2$

$\frac{x+99}{3x-2}=100$

$x+99=300x-200$

$-299x=-299$

$x=1$
• December 17th 2008, 07:10 AM
tester85
It is not correct. Should be :

log(x+99) - log(3x-2) = 2
log( x+99 / 3x-2 ) = 2
x+99 / 3x-2 = 10^2
x+99 = 100(3x-2)
x+99 = 300x - 200
299x = 299
x = 1