Thread: Write th folowing in Logarithmic Form

I am really stuck with this problem, any help would be greatly appreciated

d^5/f^2=h^0.25(c/e-g)^3

Thanks,

JP

Hello, JP!

The instructions are rather vague.

I assume we are to take logs ... then "expand" the expression.

$\displaystyle \frac{d^5}{f^2} \:=\:h^{\frac{1}{4}}\left(\frac{c}{e-g}\right)^3$

We have: .$\displaystyle \log\left(\frac{d^5}{f^2}\right) \;=\;\log\left[h^{\frac{1}{4}}\left(\frac{c}{e-g}\right)^3\right] $

. . . $\displaystyle \log(d^5) - \log(f^2) \;=\;\log\left(h^{\frac{1}{4}}\right) + \log\left(\frac{c}{e-g}\right)^3 $

. . .$\displaystyle 5\log(d) - 2\log(f) \;=\;\frac{1}{4}\log(h) + 3\log\left(\frac{c}{e-g}\right) $

. . .$\displaystyle 5\log(d) - 2\log(f) \;=\;\tfrac{1}{4}\log(h) + 3\bigg[\log(c) - \log(e-g)\bigg] $

. . .$\displaystyle 5\log(d) - 2\log(f) \;=\;\tfrac{1}{4}\log(h) + 3\log(c) - 3\log(e-g) $

thanks very much on that one