$\displaystyle 5/ (7-2x) > 0$ I am so stumped with this one. Anything I think to do with the denominator will be eliminated in the equation by the zero. Can anyone help?
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Originally Posted by chekhovita $\displaystyle 5/ (7-2x) > 0$ I am so stumped with this one. Anything I think to do with the denominator will be eliminated in the equation by the zero. Can anyone help? Think about it and you will see that you require 7 - 2x > 0 ....
Thank you very much. All frustration hath faded away.
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