Solve this Quadratic equation; x2 + 3x + 4 = 0

I thought since b^2-4ac<0 the awnser might be No Solution but im more than likely to be wrong so please help if you can..

2. Nope, you're absolutely correct .

You are right in that you have to move +4 to the other side: $-3x^2 + 4x - 4 = 0$