Solve this Quadratic equation; x2 + 3x + 4 = 0 I thought since b^2-4ac<0 the awnser might be No Solution but im more than likely to be wrong so please help if you can..
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Nope, you're absolutely correct .
Solve ; -3x2 + 4x = 4 I think i need to get the 4 on the other side but even still, don't know know where to go from there.
Try to make threads for new questions. You are right in that you have to move +4 to the other side: Now, look at the discriminant.
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