1. ## please tell me if this is correct

Im trying here........

(4x-1)(3x+2)=0

12x^2 + 5x - 2 is this correct?

2. Hello,
Originally Posted by tpoma
Im trying here........

(4x-1)(3x+2)=0

12x^2 + 5x - 2 is this correct?
If you're asked to expand, then you're correct.

But if you're asked to solve for x, it's not the method.
If you want to solve the equation (4x-1)(3x+2)=0, just remember that ab=0 if a=0 or b=0
So 4x-1=0 or 3x+2=0
This gives 2 solutions.

3. Originally Posted by tpoma
Im trying here........

(4x-1)(3x+2)=0

12x^2 + 5x - 2 is this correct?
Moo answered your two possible questions. Instead of multiplying it out and using the quadratic formula, it is much easier to solve for each term of the product.

If you let $a=3x+2=0$, then it doesn't matter what $4x-1$ is because the entire product will be zero. This enables you to solve each term of the product for zero giving you two solutions. Two answers should make sense to you because when the equation is a quadratic (of degree two).