# please tell me if this is correct

• Dec 16th 2008, 10:41 AM
tpoma
please tell me if this is correct
Im trying here........

(4x-1)(3x+2)=0

12x^2 + 5x - 2 is this correct?(Thinking)
• Dec 16th 2008, 10:54 AM
Moo
Hello,
Quote:

Originally Posted by tpoma
Im trying here........

(4x-1)(3x+2)=0

12x^2 + 5x - 2 is this correct?(Thinking)

If you're asked to expand, then you're correct.

But if you're asked to solve for x, it's not the method.
If you want to solve the equation (4x-1)(3x+2)=0, just remember that ab=0 if a=0 or b=0
So 4x-1=0 or 3x+2=0
This gives 2 solutions.
• Dec 16th 2008, 11:07 AM
colby2152
Quote:

Originally Posted by tpoma
Im trying here........

(4x-1)(3x+2)=0

If you let $a=3x+2=0$, then it doesn't matter what $4x-1$ is because the entire product will be zero. This enables you to solve each term of the product for zero giving you two solutions. Two answers should make sense to you because when the equation is a quadratic (of degree two).