# Math Help - factor theorem

1. ## factor theorem

Factorise $P(x)=x^3-7x-6$

I know that the constant term for this equation is -6 . Then , if (x-a) were to be a factor of P(x) , then a must be a factor of -6 .

Why is it so ? My book doesn't further explain .

Factorise $P(x)=x^3-7x-6$
$P(x) = (x-a)(x^2+bx+c)$