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Math Help - Height of Ball

  1. #1
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    Height of Ball

    The formula for the height of a ball as a function of time is given by the equation h = -16t^2 + vt + h, where h is the height of a ball in feet, v is the initial velocity of the ball in feet per second, h is the initial height of the ball in feet, and t is the time in seconds after the ball was thrown.
    If a ball is thrown from an initial height of 5 feet at an initial velocity of 20 feet per second, what is its height after 1 second?


    Do I plug and chug here?


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  2. #2
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    Quote Originally Posted by magentarita View Post
    The formula for the height of a ball as a function of time is given by the equation h = -16t^2 + vt + h, where h is the height of a ball in feet, v is the initial velocity of the ball in feet per second, h is the initial height of the ball in feet, and t is the time in seconds after the ball was thrown.
    If a ball is thrown from an initial height of 5 feet at an initial velocity of 20 feet per second, what is its height after 1 second?

    Do I plug and chug here?

    Yes that's right but remember to plug in h which is the initial height into the correct h in the equation as the equation has 2 h's in it.
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  3. #3
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    ok...

    Quote Originally Posted by tester85 View Post
    Yes that's right but remember to plug in h which is the initial height into the correct h in the equation as the equation has 2 h's in it.
    So, h = 5 in the function.

    Plug the rest for v and t and simplify, right?
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  4. #4
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by magentarita View Post
    So, h = 5 in the function.

    Plug the rest for v and t and simplify, right?
    Correct. The equation you should get should be h\left(t\right)=-16t^2+20t+5

    Now, what do you think h\left(1\right) should be?
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