Here is the problem:
Jane is asked to make a 37 milliliter solution of 12% HCL. However, only 8% and 15% HCL is available in the lab. How many milliliters of each solution should be use?
I started out by setting up the variables like this, but then I don't know what to do afterwards. Here is how I set up the variables.
Let x=number of ml of 8% HCl
y=number of ml of 15% HCL
Any help on how to solve this would be great appreciated!
Hello, AceComical!
Jane is asked to make a 37 milliliter solution of 12% HCL.
However, only 8% and 15% HCL is available in the lab.
How many milliliters of each solution should be use?
I started out by setting up the variables like this,
but then I don't know what to do afterwards.
Here is how I set up the variables.
Let = number of ml of 8% HCl
Let = number of ml of 15% HCL . . . . Good!
We know that the total solution is 37 ml: .
Next, we have to "talk" our way through the problem . . .
We have ml of 8% acid.
. . It contains:. ml of acid.
We have ml of 15% acid.
. . It contains: . ml of acid.
Together, they contain: . ml of acid.
But we are told that the final mixture is 37 ml which is 12% acid.
. . It contains: . ml of acid.
We just described the final amount of acid in two ways.
There is our equation: .
We have: .
Subtract: .
Substitute into [1]: .