# Thread: Using Formulae

1. ## Using Formulae

1. Use the forumula
s=ut+1/2atSQUARED
to find the value of s when:

a) u=0, t=2, a=-10 (Answer -100?)
b) u=10 t=5 a=10
c) u=20 t=1/2 a=10
d) u=-10 t=1/2 a=10
e) u=2 t=1/4 a=-5

There are others, but I think once I get this one i'll beable to do the others if you know what I mean!

@Charlie

2. Originally Posted by FB FTW
1. Use the forumula
s=ut+1/2atSQUARED
to find the value of s when:

a) u=0, t=2, a=-10 (Answer -100?)
b) u=10 t=5 a=10
c) u=20 t=1/2 a=10
d) u=-10 t=1/2 a=10
e) u=2 t=1/4 a=-5

There are others, but I think once I get this one i'll beable to do the others if you know what I mean!

@Charlie
a)
$\displaystyle s= ut+\frac{1}{2}at^2$
$\displaystyle s=0(2)+\frac{1}{2}(-10)(2)^2$
$\displaystyle s=0+\frac{1}{2}(-10)(4)$
$\displaystyle s=0+\frac{1}{2}(-40)$
$\displaystyle s=0+(-20)$
$\displaystyle s=-20$

Is that what you meant?

3. Originally Posted by euclid2
$\displaystyle s= \frac{ut+1}{2at^2}$

this formula?
No s= ut+ 1/2(half)atSQUARED

4. Thats it.

5. Originally Posted by FB FTW
No s= ut+ 1/2(half)atSQUARED
See my first post.

6. Originally Posted by FB FTW
1. Use the forumula
s=ut+1/2atSQUARED
to find the value of s when:

a) u=0, t=2, a=-10 (Answer -100?)
b) u=10 t=5 a=10
c) u=20 t=1/2 a=10
d) u=-10 t=1/2 a=10
e) u=2 t=1/4 a=-5

There are others, but I think once I get this one i'll beable to do the others if you know what I mean!

@Charlie
b)b)
$\displaystyle s=ut+\frac{1}{2}at^2$
$\displaystyle s=(10)(5)+\frac{1}{2}(10)(5)^2$
$\displaystyle s=50+\frac{1}{2}(10)(25)$
$\displaystyle s=50+\frac{1}{2}(250)$
$\displaystyle s=50+125$
$\displaystyle s=175$

7. Yeh thats it!
I've thanked, but can you do the rest please?
Thanks,
Charlie

8. Originally Posted by FB FTW
1. Use the forumula
s=ut+1/2atSQUARED
to find the value of s when:

a) u=0, t=2, a=-10 (Answer -100?)
b) u=10 t=5 a=10
c) u=20 t=1/2 a=10
d) u=-10 t=1/2 a=10
e) u=2 t=1/4 a=-5

There are others, but I think once I get this one i'll beable to do the others if you know what I mean!

@Charlie
c)
$\displaystyle s=ut+\frac{1}{2}at^2$
$\displaystyle s=(20)\frac{1}{2}+\frac{1}{2}(10)(1/2)^2$
$\displaystyle s=10+\frac{1}{2}(10)(0.25)$
$\displaystyle s=10+\frac{1}{2}(2.5)$
$\displaystyle s=10+1.25$
$\displaystyle s=11.25$

9. Originally Posted by FB FTW
1. Use the forumula
s=ut+1/2atSQUARED
to find the value of s when:

a) u=0, t=2, a=-10 (Answer -100?)
b) u=10 t=5 a=10
c) u=20 t=1/2 a=10
d) u=-10 t=1/2 a=10
e) u=2 t=1/4 a=-5

There are others, but I think once I get this one i'll beable to do the others if you know what I mean!

@Charlie
d)

s=ut+1/2at^2
s=(-10)(1/2)+1/2(10)(1/2)^2
s=-5+1/2(10)(0.25)
s=-5+1/2(2.5)
s=-5+1.25
s=-3.75

10. Originally Posted by FB FTW
1. Use the forumula
s=ut+1/2atSQUARED
to find the value of s when:

a) u=0, t=2, a=-10 (Answer -100?)
b) u=10 t=5 a=10
c) u=20 t=1/2 a=10
d) u=-10 t=1/2 a=10
e) u=2 t=1/4 a=-5

There are others, but I think once I get this one i'll beable to do the others if you know what I mean!

@Charlie
e)
s=ut+1/2at^2
s=(2)(1/4)+1/2(-5)(1/4)^2
s=1/2+1/2(-5)(0.0625)
s=0.34375

this one seems chaotic, but just plug and chug as they say

11. Thanks alot, can you do these aswell?

3)
Use the formula
v=√u^2-2as
To work out v
(√ is root, and its all of it. Like the line at the top of root goes all the way to the end of formula)

a) u=0, a=-10, s=5 (Is this one -52?)
b) u=10 a=-10 s=5
c) u=5 a=-2 s=10
d) u=2 a=1/2 s=3
e) u=1 a=1/2 s=2

Thanks!

12. Originally Posted by FB FTW
Thanks alot, can you do these aswell?

3)
Use the formula
v=√u^2-2as
To work out v
(√ is root, and its all of it. Like the line at the top of root goes all the way to the end of formula)

a) u=0, a=-10, s=5 (Is this one -52?)
b) u=10 a=-10 s=5
c) u=5 a=-2 s=10
d) u=2 a=1/2 s=3
e) u=1 a=1/2 s=2

Thanks!
a)
v=√u^2-2as
v=√(0)(0)-2(-10)(5)
v=√(20)(5)
v=√100
v=10

Like that?, where all is under the squareroot sign?

13. Originally Posted by FB FTW
Thanks alot, can you do these aswell?

3)
Use the formula
v=√u^2-2as
To work out v
(√ is root, and its all of it. Like the line at the top of root goes all the way to the end of formula)

a) u=0, a=-10, s=5 (Is this one -52?)
b) u=10 a=-10 s=5
c) u=5 a=-2 s=10
d) u=2 a=1/2 s=3
e) u=1 a=1/2 s=2

Thanks!
b)
v=√u^2-2as
v=√(10)(10)-2(-10)(5)
v=√100+20(5)
v=√100+100
v=√200
v=14.14

14. Originally Posted by euclid2
a)
v=√u^2-2as
v=√(0)(0)-2(-10)(5)
v=√(20)(5)
v=√100
v=10

Like that?, where all is under the squareroot sign?

http://i36.tinypic.com/2dhxits.png

15. Originally Posted by FB FTW
Thanks alot, can you do these aswell?

3)
Use the formula
v=√u^2-2as
To work out v
(√ is root, and its all of it. Like the line at the top of root goes all the way to the end of formula)

a) u=0, a=-10, s=5 (Is this one -52?)
b) u=10 a=-10 s=5
c) u=5 a=-2 s=10
d) u=2 a=1/2 s=3
e) u=1 a=1/2 s=2

Thanks!
c)
v=√u^2-2as
v=√(5)(5)-2(-2)(10)
v=√25+4(10)
v=√29+40
v=√69
v=8.30

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