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Math Help - Help with factoring

  1. #1
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    Help with factoring

    I need to factor these four problems:
    2
    3x -1/3


    2
    (y-5) -36


    2
    (2y-7) -1



    16
    x -1


    PLEASE, please please help me!!!!!
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  2. #2
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    Quote Originally Posted by Taylor View Post
    I need to factor these four problems:
    2
    3x -1/3


    2
    (y-5) -36


    2
    (2y-7) -1



    16
    x -1


    PLEASE, please please help me!!!!!
    What are those 2's on top?
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  3. #3
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    The twos on top are exponents.
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  4. #4
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    Quote Originally Posted by Taylor View Post
    I need to factor these four problems:
    2
    3x -1/3
    It seems factored to my divine eye.

    2
    (y-5) -36
    First 36=6^2
    Thus,
    Difference of two squares
    We have,
    (y-5-6)(y-5+6)=(y-11)(y+1)

    2
    (2y-7) -1
    Same idea since 1=1^2
    We have,
    (2y-7-1)(2y-7+1)=(2y-8)(2y-6)
    Factor the twos,
    2(y-4)*2(y-3)
    Thus,
    4(y-4)(y-3)


    16
    x -1
    Difference of two squaures on 1=1^2 we have,
    (x^8+1)(x^8-1)
    Thus,
    (x^8+1)(x^4+1)(x^4-1)
    Thus,
    (x^8+1)(x^4+1)(x^2+1)(x^2-1)
    Thus,
    (x^8+1)(x^4+1)(x^2+1)(x+1)(x-1)
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  5. #5
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    Smile

    Thank you sooooo much for helping me with the problems.
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  6. #6
    Grand Panjandrum
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    Quote Originally Posted by Taylor View Post
    I need to factor these four problems:
    2
    3x -1/3
    Factor:

    3x^2 - 1.3 = 3(x^2 - 1.9)

    the bracket is the difference of two squares, so:

    3x^2 - 1.3 = 3(x^2 - 1.9) = 3 (x-1/3) (x+1/3)

    ,,,,,,,,,,,,,,,= (3x-1)(x+1/3).

    RonL
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