I need to factor these four problems:

2

3x -1/3

2

(y-5) -36

2

(2y-7) -1

16

x -1

PLEASE, please please help me!!!!!:(

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- Oct 16th 2006, 05:33 PMTaylorHelp with factoring
I need to factor these four problems:

2

3x -1/3

2

(y-5) -36

2

(2y-7) -1

16

x -1

PLEASE, please please help me!!!!!:( - Oct 16th 2006, 05:40 PMThePerfectHacker
- Oct 16th 2006, 05:55 PMTaylor
The twos on top are exponents.

- Oct 16th 2006, 05:59 PMThePerfectHacker
It seems factored to my divine eye.

Quote:

2

(y-5) -36

Thus,

Difference of two squares

We have,

(y-5-6)(y-5+6)=(y-11)(y+1)

Quote:

2

(2y-7) -1

We have,

(2y-7-1)(2y-7+1)=(2y-8)(2y-6)

Factor the twos,

2(y-4)*2(y-3)

Thus,

4(y-4)(y-3)

Quote:

16

x -1

(x^8+1)(x^8-1)

Thus,

(x^8+1)(x^4+1)(x^4-1)

Thus,

(x^8+1)(x^4+1)(x^2+1)(x^2-1)

Thus,

(x^8+1)(x^4+1)(x^2+1)(x+1)(x-1) - Oct 16th 2006, 06:08 PMTaylor
Thank you sooooo much for helping me with the problems.

- Oct 17th 2006, 04:36 AMCaptainBlack