Two inequality questions (not related)
1. if k does not equal 0 solve the quadratic inequation for all real values
k^2x+kx+2k<0
2. Consider the quadratic equation ax^2+px+aq+q=0 where, a does not equal 0 & p and q are constants.
It is known that one of the roots of the quadratic equation is always 1 regardless of the value of a. Prove that p+q=0
Hi requal,
In that case, you could just divide by k both side since k is not zero.
Then you are just working with
You may want to check the signs though, it seems like there is no real solution...
Edit:
My bad, if k > 0, the answer is "no real solution" like shown above.
if k < 0, then the "<" switches ">" when divided by k, which would mean the answer is all real numbers.