a(y/x)^3 = 1+ c [ b(y/y-x)^3 - 1] Can anyone help me solve for x???
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Originally Posted by 021nicola a(y/x)^3 = 1+ c [ b(y/y-x)^3 - 1] Can anyone help me solve for x??? Sorry but no, not even my CAS could get an exact answer...
ok, thanks anyways....
Originally Posted by 021nicola ok, thanks anyways.... What was this question for?
solving liquid holdup in a trickle bed reactor...
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