1. ## complete the square

someone please show me how this works?

im supposed to be putting a standard formed quadratic equation into a vertex equation like this one.

4/3x^2 - 40x + 294

2. Originally Posted by TJ #99
someone please show me how this works?

im supposed to be putting a standard formed quadratic equation into a vertex equation like this one.

4/3x^2 - 40x + 294
Do you know how to complete the square?

3. to tell u the truth i know nothing thats why im askin

4. Originally Posted by TJ #99
someone please show me how this works?

im supposed to be putting a standard formed quadratic equation into a vertex equation like this one.

4/3x^2 - 40x + 294
Check out this link, I will get you started
Completing the Square
$\frac{4}{3}x^2 - 40x + 294$
$(\frac{4}{3}x^2 - 40x) + 294$
[tex] (\frac{4}{3}x^2 - 40x + 400 - 400) + 294{/math]

5. thanks i will give it a shot

6. Originally Posted by TJ #99
thanks i will give it a shot
did you get it?

7. Originally Posted by euclid2
Check out this link, I will get you started
Completing the Square
$\frac{4}{3}x^2 - 40x + 294$
$(\frac{4}{3}x^2 - 40x) + 294$
[tex] (\frac{4}{3}x^2 - 40x + 400 - 400) + 294{/math]
You can only complete the square when your a value is 1.

So...

$\frac{4}{3}x^2 - 40x + 294 = \frac{4}{3}(x^2 - 30x + \frac{441}{2})$

Go from there...