Thanks again for your continued support
I could see that there were a lot of 0's in A, so just by using matrix multiplication, I could multiply A by x and get a vector that is equal to b.
This system is not only unsolvable, it's nonsense. and can not be solved, and has to equal two different things at once in order for the system to make any sense at all.
Are you sure you copied the matrix A down correctly?
Now, i've checked and double checked and so far this matrix A is correctly copied. also, x and b still are the same.
Sorry to have caused such trouble
When we back substitute, we get an equation that has both and .
So the best we can do is write one of them in terms of the other.
In other words, we can let be whatever we like, it won't change the system. The only thing that will change is , because it depends on .