# Thread: This algebra has me stumped.

1. ## This algebra has me stumped.

can some one please give me, step by step, how to solve this problem. once I see how its done ill understand it for the other I have to do. -3(y-2)-y=5

2. If that's meant to me $\displaystyle -3(y-2)-y=5$ then you just multiply out those brackets to get...

$\displaystyle -3y+6-y=5$

Then collect the $\displaystyle y$ terms to get...

$\displaystyle -4y+6=5$

Take the 6 across to the other side to get...

$\displaystyle -4y=-1$

And finally dividing by $\displaystyle -4$ you get...

$\displaystyle y=\frac{1}{4}$

can some one please give me, step by step, how to solve this problem. once I see how its done ill understand it for the other I have to do. $\displaystyle -3(y-2)-4=5$
Have no fear, the calvary is here!

$\displaystyle -3(y-2)-4=5$

First distribute the -3 on the left side

$\displaystyle -3y+6-4=5$

Now, combine terms on the left

$\displaystyle -3y+2=5$

Next, subtract 2 from both sides

$\displaystyle -3y=3$

Finally, divide both sides by -3

$\displaystyle y=-1$

Ta-Da!!

can some one please give me, step by step, how to solve this problem. once I see how its done ill understand it for the other I have to do. -3(y-2)-y=5
$\displaystyle -3(y-2)-y=5$
$\displaystyle -3y+6-y=5$
$\displaystyle -3y-y=5-6$
$\displaystyle -4y=-1$
now finish up

5. Originally Posted by masters
Have no fear, the calvary is here!

$\displaystyle -3(y-2)-4=5$

First distribute the -3 on the left side

$\displaystyle -3y+6-4=5$

Now, combine terms on the left

$\displaystyle -3y+2=5$

Next, subtract 2 from both sides

$\displaystyle -3y=3$

Finally, divide both sides by -3

$\displaystyle y=-1$

Ta-Da!!
There is no 4 in the original equation.