# Thread: Algebra 2 help needed on exponents and logs

1. ## Algebra 2 help needed on exponents and logs

OK, I'm baaack!

Need help on the following problems and they need to be simplified:

1. -x^2y^2/x^1/2y^0=?

2. cubed root of "a" multplied by fifth root of "a"=??

And is this right???: cubed root of X^5y^5= (x^5y^5)^1/3=x^5/3y^5/3=(xy)^5/3

2. Originally Posted by JoanneMac
OK, I'm baaack!

Need help on the following problems and they need to be simplified:

1. -x^2y^2/x^1/2y^0=?

2. cubed root of "a" multplied by fifth root of "a"=??

Hello Joanne,

I'm not sure if I translated your first one correctly. You should've used parentheses to group things.

$\displaystyle -\dfrac{x^2y^2}{x^{\frac{1}{2}}y^0}=-x^{\frac{3}{2}}y^2$

$\displaystyle \sqrt[3]{a} \cdot \sqrt[5]{a}=a^{\frac{1}{3}}a^{\frac{1}{5}}=a^{\frac{5}{15} +\frac{3}{15}}=a^{\frac{8}{15}}$

Originally Posted by JoanneMac
And is this right???: cubed root of X^5y^5= (x^5y^5)^1/3=x^5/3y^5/3=(xy)^5/3

Looks good.

3. Originally Posted by JoanneMac
OK, I'm baaack!

Need help on the following problems and they need to be simplified:

1. -x^2y^2/x^1/2y^0=?

2. cubed root of "a" multplied by fifth root of "a"=??

And is this right???: cubed root of X^5y^5= (x^5y^5)^1/3=x^5/3y^5/3=(xy)^5/3

Hi JoanneMac,

It is hard to tell what was the original problem. Are you sure all your parentheses are where they are supposed to?
In other word, do you really mean $\displaystyle -x^2y^2/x^1/2y^0$? which is$\displaystyle \frac{(-x^2)*(y^2)}{(x^1)*(2y^0)}$.
Or do you mean (-x^(2y^2))/(x^(1/2y^0))? Which is$\displaystyle \frac{-x^(2y^2)}{x^(\frac{1}{2}y^0)}$.
Or something else?

4. ## The poster above..........

Masters got the equations right. Sorry, I should've used parentheses.