By drawing a graph I find x is about 0.693... but I need to show how to work it out using an algebraic method. I think I'm stuck on trying to get one x on one side of the equation if that makes sense. Please help! thanks
By drawing a graph I find x is about 0.693... but I need to show how to work it out using an algebraic method. I think I'm stuck on trying to get one x on one side of the equation if that makes sense. Please help! thanks
Hello, Alex!
Solve: .$\displaystyle e^{2x} + 4e^x - 12 \:=\:0$
Factor: .$\displaystyle \left(e^x+6\right)\left(e^x - 2\right) \;=\;0$
Then we have: .$\displaystyle \begin{Bmatrix}e^x+6 \:=\:0 & \Rightarrow & e^x \:=\:-6 & & \text{Impossible} \\ \\[-3mm]
e^x - 2 \:=\:0 & \Rightarrow & e^x \:=\:2 & \Rightarrow & \boxed{x \:=\:\ln(2)}\;\; \end{Bmatrix}$