A bullet is fired into the air with an initial upward velocity of 80 feet per second from the top of a building 96 feet high. The equation that gives the height h of the bullet at any time t is . At what thime will the bullet be 192 feet in the air?
A bullet is fired into the air with an initial upward velocity of 80 feet per second from the top of a building 96 feet high. The equation that gives the height h of the bullet at any time t is . At what thime will the bullet be 192 feet in the air?
It starts at 96ft. It is moving at 80 ftps.
h = 96 + 80t -16t^2
So we need another 96ft to reach. So we need 192 = 96 + 80t - 16t^2
In other words, 96 = 80t - 16t^2
in other words, 96 + 16t^2 = 80t
in other words, 16t^2 = 80t - 96
so.... basically, t^2 = 5t - 6
so essentially, 3^2 = 9 = 5 x 3 - 6
so basically t = 3
so fundamentally .... 196 = 96 + 240 - 144
so ummm...the time is 3 seconds................lol i think