1. ## exponents

(1)If $a^{2x-1}=b^{1-3y}$ and $a^{3x-1}=b^{2y-2}$, prove that $13xy-7x-5y+3=0$

Thanks for any help .

If $a^{2x-1}=b^{1-3y}$
than
$(2x-1)ln(a)=(1-3y)ln(b)$
so
$ln(a)/ln(b) = (1-3y)/(2x-1)$

Express the ln(a)/ln(b) from the other equation also and compare the two expression.

3. ## Re :

Thanks Skalkaz , but is there any other way besides that .

4. ## Re:

Originally Posted by mathaddict
(1)If $a^{2x-1}=b^{1-3y}$ and $a^{3x-1}=b^{2y-2}$, prove that $13xy-7x-5y+3=0$
Can this question be solved by just using laws of exponents and logarithms ?