I'm new to this and having trouble trouble breaking this down, could someone please give me a hint to get this started?
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you are saying to divide by and get 56.
This can never happen though...
Are you sure you have the right problem?
Do you see where to go now?
Given: (n + 2)!/n! = 56
(n + 2)(n + 2 - 1)(n + 2 - 2)!/n! = 56
(n + 2)(n + 1) = 56
n + 2 = 56 or n + 1 = 56
Which gives n = 54, 55
May be it helps You
Last edited by mr fantastic; Dec 9th 2008 at 12:54 AM.
Reason: Deleted link to commercial website
You solved that wrong...
thanks for the help chip, when down to
(n+9)(n-6) how do you know which to make positive and negative?
eg how do you know its not (n+6)(n-9) without substiting into the initial equation?
its simple factoring
By inspection it can be seen
Originally Posted by chiph588@ You solved that wrong...
So Small correction: n = -9, 6.
But only n = 6 is a valid solution to the original equation (to the OP: why?).
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