(n+2)/n!=56 I'm new to this and having trouble trouble breaking this down, could someone please give me a hint to get this started?
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you are saying to divide by and get 56. This can never happen though... Are you sure you have the right problem?
Sorry, (n+2)!/n!=56
Note that So Do you see where to go now?
Given: (n + 2)!/n! = 56 (n + 2)(n + 2 - 1)(n + 2 - 2)!/n! = 56 (n + 2)(n + 1) = 56 n + 2 = 56 or n + 1 = 56 Which gives n = 54, 55 May be it helps You
Last edited by mr fantastic; Dec 9th 2008 at 01:54 AM. Reason: Deleted link to commercial website
You solved that wrong... So
thanks for the help chip, when down to (n+9)(n-6) how do you know which to make positive and negative? eg how do you know its not (n+6)(n-9) without substiting into the initial equation?
its simple factoring given that doing foil... So and By inspection it can be seen
Originally Posted by chiph588@ You solved that wrong... So Small correction: n = -9, 6. But only n = 6 is a valid solution to the original equation (to the OP: why?).
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