1. ## shading the graph

ok i have this liner inequation 4x + y < 8 i solved for x and y and got 0,8 0,2 the book says this is right. so basicly next i would find numbers on the opisite x and y axis and add them to problem like this

4(-2) + -3 <8 if its true i would shade on the right side of the line and if its false i would shade the left side of the line. is this right ?

2. Originally Posted by robpez
ok i have this liner inequation 4x + y < 8 i solved for x and y and got 0,8 0,2 the book says this is right. so basicly next i would find numbers on the opisite x and y axis and add them to problem like this

4(-2) + -3 <8 if its true i would shade on the right side of the line and if its false i would shade the left side of the line. is this right ?
The boundary line line for the inequality is:

4x + y =8

The two intercepts are obtained by putting x=0 and solving for y,
and by putting y=0 and solving for x. Doing this we get that the
two intercepts are (0,8) and (2,0). The boundary line is the line going
through these two points.

Now it seems to me that the test point (-2,-3) is to the left and below
the line through (0,8) and (2,0), and as:

4(-2) - 3 < 8

this point is in the region that satisfies the inequality, so you should
shade the region to the left of the line.

RonL