flipping number question..

what is the math formula(algorithm) for flipping any number like:
47->74
1655 -> 5561

12345->54321

1190 -> 911
??

add up the individual digits. multiply by 11. subtract the original #.

for instance:

x = 23

2 + 3 = 5

5* 11 = 55

55 - 23 = 32

Quote:

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Originally Posted by Mentia

add up the individual digits. multiply by 11. subtract the original #.

for instance:

x = 23

2 + 3 = 5

5* 11 = 55

55 - 23 = 32

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Epic.