# expanding brackets

• Dec 8th 2008, 10:00 AM
newbie2008
expanding brackets
An easy one, but still...

The problem is expanding (((2+h)^2)-4)/h

first off do I need all those brackets to be clear when it's written on one line? :)

How do you get to the answer of 4h+(h^2)/h? I don't get that...

Could you explain where I'm going wrong?

Thanks
• Dec 8th 2008, 10:07 AM
Bruce
Quote:

Originally Posted by newbie2008
An easy one, but still...

The problem is expanding (((2+h)^2)-4)/h

first off do I need all those brackets to be clear when it's written on one line? :)

How do you get to the answer of 4h+(h^2)/h? I don't get that...

Could you explain where I'm going wrong?

Thanks

for the expansion, $\frac {(2+h)^2-4}{h}$ you need to first square (2+h) which is just h^2 + 4h + 4 (if you need more explanation for this please reply and say so), then you are subtracting 4 so you are left with h^2 + 4h.

you can still make this answer simpler if you want by dividing it:

$\frac {4h+h^2}{h}$ you are dividing by h and so 4h/h is just 4, and h^2/h is just h, so your final answer is h + 4