1. ## 1 = 2

I know there is error in this but! If i can substitute 1 for x here.

Originally Posted by http://www.amatecon.com/1equals2errors.html

x = 1 set x equal to 1
x2 = x multiply both sides by x
x2 - 1 = x - 1 subtract 1 from both sides
(x - 1)(x + 1) = x - 1 separate left side into factors
x + 1 = 1 divide both sides by (x - 1)
1 + 1 = 1 substitute 1 for x
2 = 1
Originally Posted by Error

Division by (x-1) is not allowed since x=1 and therefor x-1=0 and division by zero is an undefined operation.
Why can't I substitute 1 for x in this problem.

Substitute 1 for x.

1+1=x

2=1 ! omg.

Division by (x-1) is not allowed since x=1 and therefor x-1=0 and division by zero is an undefined operation.
Division by zero leads to bogus proofs like this.

3. the correct mathematical notation is:
limit as x tends to 1 for (x^2-1)/(x-1)
this limit is equal to 2 and you cannot just get (x-1) out of the limit and multiply it by to on the RHS.
God Bless

4. The point is, he's let $\displaystyle \frac{0}{0}=1$ when actually it's indeterminate.

5. 0/0 is 0

Plain and simple.

but
x-1=k-1
if x = 2 and k = 3

2-1=3-1
1=2

NVM x-1=k-1 would not be true !!! sorry I'm stoooopid.

6. Yep, all you can say about x-1=k-1 is x=k, and nope, $\displaystyle \frac{0}{0}\ne0$, it is simply not defined.

7. Originally Posted by Error
0/0 is 0

Plain and simple.

but
x-1=k-1
if x = 2 and k = 3

2-1=3-1
1=2

NVM x-1=k-1 would not be true !!! sorry I'm stoooopid.
Let me just say that a thread which goes against the basic principles of maths (like 1+1=2 and 0/0 = 0) is bound to be closed and deleted. Plus it does everything but earn you respect.

8. Originally Posted by Error
0/0 is 0

Plain and simple.
If you are serious with this you need to go back to school and repeat elementary arithmetic.

CB