1. ## complex numbers

Find the complex number z such that:-

$(1+3i)+((4-5i)/(z))=(-2-3i)$

thanks for any help..

2. Originally Posted by omibayne
Find the complex number z such that
$(1+3i)+((4-5i)/(z))=(-2-3i)$
If you solve for z: $z=\frac {4-5i}{(-2-3i)-(1+3i)}$

3. Originally Posted by Plato
If you solve for z: $z=\frac {4-5i}{(-2-3i)-(1+3i)}$

i got $z=\frac{18+39i}{45}$....is it right?

4. Originally Posted by omibayne
i got $z=\frac{18+39i}{45}$....is it right?
That's what I get when I work it out