1. ## log equation help!

Solve the equation. log (3x) = log 5 + log (x - 2)

2. Recall that $\displaystyle \log{A}+\log{B}=\log{(AB)}$. Therefore, your equation can be rewritten as:

$\displaystyle \log{3x}=\log{(5(x-2))}$

Taking the antilog of both sides yields:

$\displaystyle 3x = 5x-10$

$\displaystyle x = \ldots$