Solve the equation. log (3x) = log 5 + log (x - 2)
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Recall that $\displaystyle \log{A}+\log{B}=\log{(AB)}$. Therefore, your equation can be rewritten as: $\displaystyle \log{3x}=\log{(5(x-2))}$ Taking the antilog of both sides yields: $\displaystyle 3x = 5x-10$ $\displaystyle x = \ldots$
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