3/4, 1 , 7/6 , 9/7
Hello, juliak!
Write all of them as fractions . . .Sequence: .$\displaystyle \frac{3}{4},\;1,\;\frac{7}{6},\;\frac{9}{7},\;\hdo ts$
We have: .$\displaystyle \frac{3}{4},\;\frac{5}{5},\;\frac{7}{6},\;\frac{9} {7},\;\hdots $
Got it?
The denominators are consecutive integers starting at 4: .$\displaystyle n+3$
The numerators are consecutive odd integers starting at 3: .$\displaystyle 2n+1$
The general term is: .$\displaystyle a_n \;=\;\frac{2n+1}{n+3} $