find the missing numbers 3/5 = a/10 = b/20
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Originally Posted by starslacker find the missing numbers 3/5 = a/10 = b/20 Let's take them one at a time. 3/5 = a/10 Multiply both sides by 10: 10*(3/5) = 10*(a/10) 6 = a For b: 3/5 = b/20 Multiply both sides by 20: 20*(3/5) = 20*(b/20) 12 = b -Dan
Originally Posted by starslacker find the missing numbers 3/5 = a/10 = b/20 a=6, b=18
Originally Posted by poohbearjkr a=6, b=18 b can't be 18. 18/20 = 9/10 which is not the same as 3/5. -Dan
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