Does any one know how to successfully complete simulataneous equations I have been trying to solve this one for ages and just cant do it is stressing me out
3p1-4p1=57
2p1+2p2-10=0
I'd appreciate any help
thanks
I think there is an typo..It should be
3p1-4p2=57---------[1]
2p1+2p2-10=0-------[2]
Here is the solution:
Multiply 2 in equation [2]
Now we have;
$\displaystyle 3p_1-4p_2=57---[1]$
$\displaystyle 4p_1+4p_2=20--[2]$
Add them...
$\displaystyle 7p_1=77$
$\displaystyle p_1=11$
Substitute in [1]
We have $\displaystyle -4p_2=24$
$\displaystyle p_2=-6$
So $\displaystyle p_1=11$ and $\displaystyle p_2=-6$