hi anyone help me totally stuck on this question thanks first time on forum.
3r-2t=0.2
r+s=2.4
4s-t=7.3
Thatīs what I did:
First eliminate $\displaystyle r$ from the 1st and 2nd equation
$\displaystyle 3r-2t=0,2$
$\displaystyle -3r-3s=-7,2$
$\displaystyle -----------$
$\displaystyle -3s-2t=-7,0$
Now eliminate $\displaystyle t$ from this one and the 3rd equation
$\displaystyle 3s+2t=7,0$
$\displaystyle 8s-2t=14,6$
$\displaystyle -----------$
$\displaystyle 11s=21,6$
so $\displaystyle s=21,6/11$ I donīt know if you want to give an approximate of that number, if you want its exact value, it is $\displaystyle s=108/55$
Now you can start the back-substitution in order to get $\displaystyle t$ and $\displaystyle r$
Hope it helped...