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Math Help - small question

  1. #1
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    small question

    what do i use to get the bases the same.. 8^x = 1/32^x-2
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  2. #2
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    Hello, larasanut!

    What do i use to get the bases the same? . . . 8^x \:=\: \frac{1}{32^{x-2}}

    Note that: . 8 \,=\,2^3\:\text{ and }\:32 \,=\,2^5

    So we have: . \left(2^3\right)^x \;=\;\frac{1}{(2^5)^{x-2}} \;=\;\frac{1}{2^{5x-10}} \;=\;2^{-(5x-10)}

    Hence: . 2^{3x} \;=\;2^{-5x+10} . . . Got it?

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  3. #3
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    YUP THANKS
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