Hello, Mac Addict!

Here's a back-door solution . . .

Jim and Freda live 3 miles apart.

They both leave their houses at the same time and walk to meet each other.

Jim walks at 2.5 miles/hour and Freda walks at 3.5 miles/hour.

How far will Jim walk before he meets Freda?

They have a combined speed of: . mph.

To cover 3 miles at 6 mph, it will take them a half-hour.

In that time, Jim has covered: . miles.

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Assuming that wemustuse algebra . . .

We will use: . }" alt="\text{(Distance)} \:=\:\text{(Speed)} \times \text{}" />

Let = time for them to meet (in hours).

Jim walks at 2.5 mph.

In hours, he walks: miles.

Freda walks at 3.5 mph.

In hours, she walks: miles.

Together, they cover 3 miles: .

. . Then: . hour.

In that time, Jim walked: . miles.