I need help with a couple of rationalization questions. I am totally confused. square root 5x minus 6 / squareroot 5x plus 3 (squareroot 2+y plus squareroot 2-y)/y
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Originally Posted by shiel8 I need help with a couple of rationalization questions. I am totally confused. square root 5x minus 6 / squareroot 5x plus 3 (squareroot 2+y plus squareroot 2-y)/y Is it (1) $\displaystyle \frac{\sqrt{5x-6}}{\sqrt{5x+3}}$ ? or (2) $\displaystyle \frac{\sqrt{5x}-6}{\sqrt{5x}+3}$ Also group what's under the radical in your second problem as well.
for the second questions it's 2+y under squareroot symbol minus 2-y under squareroot symbol all over y how do you enter info in the format you're using? It'd be much easier to post if I knew how to do that.
Originally Posted by shiel8 for the second questions it's 2+y under squareroot symbol minus 2-y under squareroot symbol all over y how do you enter info in the format you're using? It'd be much easier to post if I knew how to do that. Have a look here: http://www.mathhelpforum.com/math-he...-tutorial.html Use a factor such that you get a sum of squares in the denominator: $\displaystyle \dfrac{\sqrt{5x} - 6}{\sqrt{5x} + 3}=\dfrac{\sqrt{5x} - 6}{\sqrt{5x} + 3} \cdot \dfrac{\sqrt{5x} - 3}{\sqrt{5x} - 3}= \dfrac{5x-9\sqrt{5x} +18}{5x-9}$
Thanks Earboth. Hopefully this works right. The other question I need help with is: $\displaystyle \frac{\sqrt{2+y} + \sqrt{2-y}}{y}$
Last edited by shiel8; Dec 3rd 2008 at 10:36 AM. Reason: fixing latex
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